Alexandria Bay, New York

US village in New York State

Alexandria Bay is a village in Jefferson County, New York, United States, within the town of Alexandria. It is in the Thousand Islands region of northern New York. The population of the village was 1,078 at the 2010 United States Census.[2]

Alexandria Bay, New York
A panorama of Alexandria Bay taken from nearby Boldt Castle
A panorama of Alexandria Bay taken from nearby Boldt Castle
Motto(s): 
"Heart of the Thousand Islands"
Alexandria Bay is located in New York
Alexandria Bay
Alexandria Bay
Alexandria Bay is located in the United States
Alexandria Bay
Alexandria Bay
Coordinates: 44°20′9″N 75°54′53″W / 44.33583°N 75.91472°W / 44.33583; -75.91472Coordinates: 44°20′9″N 75°54′53″W / 44.33583°N 75.91472°W / 44.33583; -75.91472
CountryUnited States
StateNew York
CountyJefferson
TownAlexandria
Area
 • Total1.53 sq mi (3.95 km2)
 • Land0.76 sq mi (1.98 km2)
 • Water0.76 sq mi (1.97 km2)
Elevation
284 ft (87 m)
Population
 (2010)
 • Total1,078
 • Estimate 
(2018)[1]
1,044
 • Density1,407/sq mi (543.3/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
13607
Area code(s)315
FIPS code36-01187
GNIS feature ID0942309
Websitewww.villageofalexandriabay.com

ReferencesEdit

  1. "Population and Housing Unit Estimates". Retrieved February 16, 2020.
  2. "Geographic Identifiers: 2010 Census Summary File 1 (G001): Alexandria Bay village, New York". American Factfinder. U.S. Census Bureau. Archived from the original on February 13, 2020. Retrieved September 4, 2018.