1956 UEFA European Under-18 Championship

international football competition

The UEFA European Under-18 Championship 1956 Final Tournament was held in Hungary. During this edition, only group matches were played and no winner was declared. This was done to prevent a leftover of competition. Hungary, Italy, Romania and Czechoslovakia were the four group winners.

1956 UEFA European Under-18 Championship
Tournament details
Host countryHungary
Dates28 March – 2 April
Teams16
1955
1957

The following teams entered the tournament:

Group A

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Teams Pld W D L GF GA GD Pts
  Hungary 3 2 1 0 6 3 +3 5
  West Germany 3 1 1 1 2 2 0 3
  Bulgaria 3 1 0 2 3 4 –1 2
  England 3 1 0 2 5 7 –2 2


28 March Hungary   0–0   West Germany
Bulgaria   2–1   England
30 March West Germany   1–0   Bulgaria
Hungary   4–2   England
1 April Hungary   2–1   Bulgaria
England   2–1   West Germany

Group B

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Teams Pld W D L GF GA GD Pts
  Italy 3 2 0 1 5 2 +3 4
  France 3 2 0 1 4 3 +1 4
  Saarland 3 1 1 1 3 5 –2 3
  Belgium 3 0 1 2 5 7 –2 1


28 March Saarland   1–0   France
Italy   2–1   Belgium
30 March France   3–2   Belgium
Italy   3–0   Saarland
1 April Saarland   2–2   Belgium
France   1–0   Italy

Group C

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Teams Pld W D L GF GA GD Pts
  Romania 3 2 1 0 6 2 +4 5
  Poland 3 1 1 1 4 4 0 3
  Yugoslavia 3 0 2 1 2 3 –1 2
  Austria 3 1 0 2 4 7 –3 2


29 March Romania   1–1   Yugoslavia
Poland   3–2   Austria
31 March Austria   1–0   Yugoslavia
Romania   1–0   Poland
2 April Romania   4–1   Austria
Poland   1–1   Yugoslavia

Group D

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Teams Pld W D L GF GA GD Pts
  Czechoslovakia 3 2 1 0 4 1 +3 5
  Turkey 3 1 1 1 4 2 +2 3
  East Germany 3 0 3 0 3 3 0 3
  Greece 3 0 1 2 1 6 –5 1


29 March Czechoslovakia   2–0   Greece
East Germany   1–1   Turkey
31 March Czechoslovakia   1–1   East Germany
Turkey   3–0   Greece
2 April Czechoslovakia   1–0   Turkey
East Germany   1–1   Greece

Other websites

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