1900 United States presidential election
29th quadrennial U.S. presidential election
The 1900 United States presidential election was the 29th election in the history of the United States. It happened on November 6, 1900. William McKinley, the incumbent president, won reelection.
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447 members of the Electoral College 224 electoral votes needed to win | ||||||||||||||||||||||||||||||||
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| Turnout | 73.7%[1]  5.9 pp | |||||||||||||||||||||||||||||||
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 Presidential election results map. Red denotes states won by McKinley/Roosevelt, blue denotes those won by Bryan/Stevenson. Numbers indicate the number of electoral votes allotted to each state. | ||||||||||||||||||||||||||||||||
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This election was a rematch of 1896 being held between incumbent President William McKinley of Ohio and former Congressman William Jennings Bryan of Nebraska. McKinley won the election with 292 electoral votes. Bryan got only 155 electoral votes.
Candidates
changeRepublican Party
change- William McKinley, 25th President of the United States (1897-1901)
Democratic Party
change- William Jennings Bryan, former Congressman of Nebraska (1891-1895) and 1896 Candidate (Nominee)
References
change- ↑ "National General Election VEP Turnout Rates, 1789-Present". United States Election Project. CQ Press.
