Alexander, New York

town in New York, United States
(Redirected from Alexander (town), New York)

Alexander is a town in Genesee County, New York, United States. The population was 2,491 at the 2020 census.[2] The town is named after Alexander Rea, an early settler. It includes a village also named Alexander.

Alexander, New York
Town hall, the former Alexander Classical School
Town hall, the former Alexander Classical School
Location in Genesee County and the state of New York.
Location in Genesee County and the state of New York.
Location of New York in the United States
Location of New York in the United States
Coordinates: 42°54′06″N 78°15′23″W / 42.90167°N 78.25639°W / 42.90167; -78.25639
CountryUnited States
StateNew York
CountyGenesee County
Incorporated1812
Named forAlexander Rea
Area
 • Total35.56 sq mi (92.11 km2)
 • Land35.47 sq mi (91.86 km2)
 • Water0.10 sq mi (0.25 km2)
Elevation
932 ft (284 m)
Population
 • Total2,491
 • Density70.23/sq mi (27.12/km2)
Time zoneUTC-5 (EST)
 • Summer (DST)UTC-4 (EDT)
ZIP code
14005
Area code585
FIPS code3603701165
Websitewww.townofalexander.com

References change

  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 6, 2024.
  2. 2.0 2.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Alexander town, Genesee County, New York". United States Census Bureau. Retrieved March 6, 2024.