Cuba, New York
town in Allegany County, New York, United States
Cuba is a town in Allegany County, New York, United States. As of the 2020 United States Census, the total population was 3,126.[2]
Cuba, New York | |
---|---|
Coordinates: 42°13′04″N 78°16′31″W / 42.21778°N 78.27528°W | |
Country | United States |
State | New York |
County | Allegany |
Area | |
• Total | 35.80 sq mi (92.73 km2) |
• Land | 35.10 sq mi (90.91 km2) |
• Water | 0.70 sq mi (1.82 km2) |
Population | |
• Total | 3,126 |
• Density | 89.06/sq mi (34.39/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
FIPS code | 36-003-19367 |
Website | https://www.cubany.org/ |
References
change- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 7, 2024.
- ↑ 2.0 2.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Cuba town, Allegany County, New York". United States Census Bureau. Retrieved March 7, 2024.