Garden Grove, Iowa
human settlement in Decatur County, Iowa, United States of America
Garden Grove is a city in Decatur County, in Iowa in the United States. There were 174 people at the time of the 2020 census.[1]
Garden Grove | |
|---|---|
 | |
 | |
| Coordinates: 40°49′35″N 93°36′28″W | |
| Country | United States |
| State | Iowa |
| County | Decatur County |
| Area | |
| • Total | 0.69 sq mi (1.79 km2) |
| • Land | 0.69 sq mi (1.79 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 1,112 ft (339 m) |
| Population | |
| • Total | 174 |
| • Density | 257.40/sq mi (99.38/km2) |
| Area code | 641 |
Geography change
Garden Grove is located at 40°49′35″N 93°36′28″W (40.826479, -93.607732).
History change
A strong EF2 tornado hit the town on March 5, 2022.
Demographics change
2010 census change
At the 2010 census there were 211 people in 49 families, in 78 houses in the city.
The medium age was 38.1 years.
2000 census change
At the 2000 census there were 250 people in 96 houses, in 64 families.
References change
- ↑ 1.0 1.1 "Garden Grove city, Iowa". United States Census Bureau. Retrieved November 6, 2023.
- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.