Garden Grove, Iowa
human settlement in Decatur County, Iowa, United States of America
Garden Grove is a city in Decatur County, in Iowa in the United States. There were 174 people at the time of the 2020 census.[1]
Garden Grove | |
|---|---|
 | |
 | |
| Coordinates: 40°49′35″N 93°36′28″W | |
| Country | United States |
| State | Iowa |
| County | Decatur County |
| Area | |
| • Total | 0.69 sq mi (1.79 km2) |
| • Land | 0.69 sq mi (1.79 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 1,112 ft (339 m) |
| Population | |
| • Total | 174 |
| • Density | 257.40/sq mi (99.38/km2) |
| Area code | 641 |
Geography
changeGarden Grove is located at 40°49′35″N 93°36′28″W (40.826479, -93.607732).
History
changeA strong EF2 tornado hit the town on March 5, 2022.
Demographics
change2010 census
changeAt the 2010 census there were 211 people in 49 families, in 78 houses in the city.
The medium age was 38.1 years.
2000 census
changeAt the 2000 census there were 250 people in 96 houses, in 64 families.
References
change- ↑ 1.0 1.1 "Garden Grove city, Iowa". United States Census Bureau. Retrieved November 6, 2023.
- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.