Jefferson, South Dakota
city in South Dakota, United States
Jefferson is a city in the southeastern part of the U.S. state of South Dakota. It is located in Union County, and 475 people lived there at the 2020 census.[4] Jefferson became a city in 1895.[5]
Jefferson, South Dakota | |
|---|---|
 Location in Union County and the state of South Dakota | |
| Coordinates: 42°36′15″N 96°33′58″W / 42.60417°N 96.56611°W | |
| Country | United States |
| State | South Dakota |
| County | Union |
| Incorporated | 1895[1] |
| Area | |
| • Total | 0.51 sq mi (1.32 km2) |
| • Land | 0.51 sq mi (1.32 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 1,116 ft (340 m) |
| Population | |
| • Total | 475 |
| • Density | 931.37/sq mi (359.27/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 57038 |
| Area code | 605 |
| FIPS code | 46-32700 |
| GNIS feature ID | 1267441[3] |
References
change- ↑ "SD Towns" (PDF). South Dakota State Historical Society. Archived from the original (PDF) on 2010-02-10. Retrieved 2010-02-13.
- ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved October 15, 2022.
- ↑ 3.0 3.1 U.S. Geological Survey Geographic Names Information System: Jefferson, South Dakota
- ↑ 4.0 4.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson city, South Dakota". United States Census Bureau. Retrieved February 15, 2024.
- ↑ "SD Towns" (PDF). South Dakota State Historical Society. Retrieved 2014-02-16.
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