Pomeroy, Iowa
human settlement in Calhoun County, Iowa, United States of America
Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 526 in 2020.[2]
Pomeroy, Iowa | |
---|---|
Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W | |
Country | United States |
State | Iowa |
County | Calhoun |
Government | |
• Type | Mayor-council |
Area | |
• Total | 2.05 sq mi (5.30 km2) |
• Land | 2.05 sq mi (5.30 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 1,240 ft (378 m) |
Population | |
• Total | 526 |
• Density | 256.84/sq mi (99.17/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 50575 |
Area code | 712 |
FIPS code | 19-64065 |
GNIS feature ID | 0460354 |
Website | City of Pomeroy |
Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.
References
change- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ↑ 2.0 2.1 "Pomeroy city, Iowa". United States Census Bureau. Retrieved November 9, 2023.
Other websites
change- Official City of Pomeroy website Archived 2007-11-13 at the Wayback Machine