Pomeroy, Iowa

human settlement in Calhoun County, Iowa, United States of America

Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 710 in 2000.

City of Pomeroy
Location of Pomeroy in the state of Iowa.
Location of Pomeroy in the state of Iowa.
City of Pomeroy is located in Iowa
City of Pomeroy
City of Pomeroy
Coordinates: Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361
CountryUnited States
 • MayorDavid Berger
 • Total2.0 sq mi (5.3 km2)
 • Land2.0 sq mi (5.3 km2)
 • Water0.0 sq mi (0.0 km2)
1,240 ft (378 m)
 • Total710
 • Density347.4/sq mi (134.1/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code(s)712
FIPS code19-64065[1]
GNIS feature ID0460354[2]

Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.


  1. "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  2. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.

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