Pomeroy, Iowa

human settlement in Calhoun County, Iowa, United States of America

Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 526 in 2020.[2]

Pomeroy, Iowa
Location of Pomeroy, Iowa
Location of Pomeroy, Iowa
Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361
Country United States
State Iowa
CountyCalhoun
Government
 • TypeMayor-council
Area
 • Total2.05 sq mi (5.30 km2)
 • Land2.05 sq mi (5.30 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
1,240 ft (378 m)
Population
 • Total526
 • Density256.84/sq mi (99.17/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP code
50575
Area code712
FIPS code19-64065
GNIS feature ID0460354
WebsiteCity of Pomeroy

Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.

References change

  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. 2.0 2.1 "Pomeroy city, Iowa". United States Census Bureau. Retrieved November 9, 2023.

Other websites change