Romulus, New York
town in Seneca County, New York, United States
Romulus is a town in Seneca County, New York, United States. The population was 3,203 at the 2020 census.[3]
Romulus, New York | |
---|---|
Coordinates: 42°43′19″N 76°50′26″W / 42.72194°N 76.84056°W | |
Country | United States |
State | New York |
County | Seneca |
Settled | 1789 |
Established | March 5, 1794[1] |
Area | |
• Total | 51.38 sq mi (133.08 km2) |
• Land | 37.79 sq mi (97.88 km2) |
• Water | 13.59 sq mi (35.20 km2) |
Elevation | 758 ft (231 m) |
Population | |
• Total | 3,203 |
• Density | 84.75/sq mi (32.72/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 14541 |
Area code(s) | 315, 607 and 680 |
FIPS code | 36-63440 |
GNIS feature ID | 0979431 |
Website | http://www.romulustown.com/ |
References
change- ↑ Sullivan, James; Williams, Melvin E.; Conklin, Edwin P.; Fitzpatrick, Benedict, eds. (1927), "Chapter IV. Seneca County.", History of New York State, 1523–1927 (PDF), vol. 2, New York City, Chicago: Lewis Historical Publishing Co., p. 635, hdl:2027/mdp.39015019994048, Wikidata Q114149636
- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 8, 2024.
- ↑ 3.0 3.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Romulus town, Seneca County, New York". United States Census Bureau. Retrieved March 8, 2024.