Seymour, Iowa

city in Iowa, United States

Seymour is a city in Iowa in the United States. Seymour is a very tiny city.

Seymour, Iowa
City
Location of Seymour, Iowa
Location of Seymour, Iowa
Coordinates: 40°40′56″N 93°07′16″W / 40.68222°N 93.12111°W / 40.68222; -93.12111
CountryUSA
State Iowa
CountyWayne
Area
 • Total2.39 sq mi (6.20 km2)
 • Land2.39 sq mi (6.20 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation1,076 ft (328 m)
Population
 • Total634
 • Density265.05/sq mi (102.32/km2)
Time zoneUTC−6 (Central (CST))
 • Summer (DST)UTC−5 (CDT)
ZIP code
52590
Area code641
FIPS code19-71760
GNIS feature ID2395851[2]

References change

  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. 2.0 2.1 U.S. Geological Survey Geographic Names Information System: Seymour, Iowa
  3. "Seymour city, Iowa". United States Census Bureau. Retrieved November 9, 2023.