1992 United States presidential election

52nd quadrennial U.S. presidential election

The 1992 United States presidential election happened on November 3, 1992. Bill Clinton, the Democratic candidate and Governor of Arkansas, won the election. He defeated the incumbent president, George H. W. Bush, who was a Republican, and Ross Perot, an independent candidate.

1992 United States presidential election

← 1988 November 3, 1992 1996 →

538 members of the Electoral College
270 electoral votes needed to win
Turnout55.2%[1] Increase 5.0 pp
 
Nominee Bill Clinton George H. W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 370 168 0
States carried 32 + DC 18 0
Popular vote 44,909,806 39,104,550 19,743,821
Percentage 43.0% 37.4% 18.9%

Presidential election results map. Red denotes states won by Bush/Quayle, Blue denotes those won by Clinton/Gore.

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

Clinton got 370 electoral votes, Bush got 168, and Perot got 0. A person running for president needs to get 270 to win.

George H.W. Bush may have lost the election for several reasons. He broke his promise of "Read my lips: no new taxes" by increasing taxes during his term. Some of his most well-known accomplishments during his presidency came from his foreign policy, and because of the Cold War and Gulf War being over, foreign policy became a smaller issue, as the economy became a bigger issue, since the economy was bad.

Prior to 2020, this was the last election where a candidate won the presidency without winning Florida.

Candidates change

Republican Party change

Republican candidates

Candidates gallery change

Democratic Party change

Democratic candidates

Candidates gallery change

Other websites change

References change

  1. "Dave Leip's Atlas of U.S. Presidential Elections". Uselectionatlas.org. Retrieved October 21, 2012.